2[x-(2x+9)+8]=2(x+1)

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Solution for 2[x-(2x+9)+8]=2(x+1) equation:


Simplifying
2[x + -1(2x + 9) + 8] = 2(x + 1)

Reorder the terms:
2[x + -1(9 + 2x) + 8] = 2(x + 1)
2[x + (9 * -1 + 2x * -1) + 8] = 2(x + 1)
2[x + (-9 + -2x) + 8] = 2(x + 1)

Reorder the terms:
2[-9 + 8 + x + -2x] = 2(x + 1)

Combine like terms: -9 + 8 = -1
2[-1 + x + -2x] = 2(x + 1)

Combine like terms: x + -2x = -1x
2[-1 + -1x] = 2(x + 1)
[-1 * 2 + -1x * 2] = 2(x + 1)
[-2 + -2x] = 2(x + 1)

Reorder the terms:
-2 + -2x = 2(1 + x)
-2 + -2x = (1 * 2 + x * 2)
-2 + -2x = (2 + 2x)

Solving
-2 + -2x = 2 + 2x

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-2x' to each side of the equation.
-2 + -2x + -2x = 2 + 2x + -2x

Combine like terms: -2x + -2x = -4x
-2 + -4x = 2 + 2x + -2x

Combine like terms: 2x + -2x = 0
-2 + -4x = 2 + 0
-2 + -4x = 2

Add '2' to each side of the equation.
-2 + 2 + -4x = 2 + 2

Combine like terms: -2 + 2 = 0
0 + -4x = 2 + 2
-4x = 2 + 2

Combine like terms: 2 + 2 = 4
-4x = 4

Divide each side by '-4'.
x = -1

Simplifying
x = -1

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